Short circuit current calculation
Prospective short-circuit current (PSCC) is the maximum current that can flow in an electrical system when a solid short circuit occurs. Its value is determined by the source voltage and the total impedance of the fault loop, typically expressed as Icc = V / Z. In standard domestic installations its magnitude is around a few thousand amperes, while in high-power industrial systems it can exceed hundreds of thousands of amperes.
Fundamental formula
Section titled “Fundamental formula”Icc = V / Z
Where: Icc = short-circuit current (A) V = voltage at the fault point (V) Z = total impedance of the fault loop (Ω)
Variables and units
Section titled “Variables and units”| Variable | Symbol | Unit | Description |
|---|---|---|---|
| Short-circuit current | Icc | A | Ampere |
| Nominal voltage | V | V | Volt |
| Loop impedance | Z | Ω | Ohm |
Impedance Z includes the resistance and reactance of all series elements: supply transformer, conductors, connections, and contact impedance.
Calculation procedure
Section titled “Calculation procedure”- Determine the nominal voltage at the fault point (phase‑neutral for single-phase faults, or phase‑phase for two-phase/three-phase faults).
- Calculate the total impedance of the short-circuit loop (source + wiring + splices) by measurement or summing of components.
- Apply the formula Icc = V / Z to obtain the symmetric RMS current.
- For asymmetric faults (three-phase, phase‑ground, etc.) use symmetrical components and asymmetry factors according to the applicable standard, which raise the peak value to approximately 2.5 times the symmetric peak value.
Calculation example
Section titled “Calculation example”A single-phase supply of 230 V / 50 Hz has a measured loop impedance of 0.1 Ω. The prospective short-circuit current is:
Icc = 230 V / 0.1 Ω = 2300 A.
The protective device at that point must have a breaking capacity greater than 2.3 kA to safely interrupt the fault.
Thermal and electrodynamic stresses
Section titled “Thermal and electrodynamic stresses”During the short circuit, the conductors and switch contacts experience abrupt temperature rises and electromagnetic forces that condition the design of busbars and supports.
Temperature rise
Section titled “Temperature rise”Heating occurs in adiabatic regime (no heat transfer to the environment) during the few milliseconds the fault lasts. The temperature rise can be estimated with:
ΔT = (I² · R · t) / (m · c)
| Variable | Meaning | SI unit | Imperial unit |
|---|---|---|---|
| ΔT | Temperature rise | °C | °F |
| I | Short-circuit current (RMS value) | A | A |
| R | Conductor resistance | Ω | Ω |
| t | Fault duration | s | s |
| m | Conductor mass | kg | lb |
| c | Specific heat of material | J/(kg·°C) | BTU/(lb·°F) |
In aluminum, mechanical strength degrades above 160 °C / 320 °F, so the design must limit the thermal rise by sufficient cross-section and ultra-fast clearing time.
Electrodynamic force between conductors
Section titled “Electrodynamic force between conductors”The force developed between two parallel conductors carrying the short-circuit current is calculated with the adapted Ampère formula:
F = (μ₀ · I² · L) / (2π · S)
(SI: F in N, L and S in m)
For imperial units (L and S in inches, F in pounds‑force):
Flbf = (2.54×10⁻⁷ · I² · L) / S
| Variable | Meaning | SI unit | Imperial unit |
|---|---|---|---|
| I | Short-circuit current (asymmetric peak value) | A | A |
| L | Active length of conductors | m | in |
| S | Center-to-center distance of conductors | m | in |
| F | Force between conductors | N | lbf |
For rectangular conductors, a correction factor K is applied based on the width/thickness ratio and separation; K is maximum in very thin busbars and tends to 1 in circular sections.
Design considerations
Section titled “Design considerations”- The breaking capacity of circuit breakers and fuses must exceed the maximum prospective Icc at the installation point; otherwise, the electric arc will not be extinguished.
- The minimum Icc at a socket outlet must be at least 20 times the circuit rated current, to ensure fast operation of protections and limit touch voltage during ground faults.
- In industrial networks, motors and generators contribute to the short-circuit current during the first cycles, so their subtransient impedance must be included in the calculation.
- Busbars and their supports must be dimensioned to withstand the maximum force generated by the asymmetric peak (approximately 2.5 times the symmetric peak current), also considering possible mechanical resonance phenomena.
Frequently Asked Questions (FAQ)
Section titled “Frequently Asked Questions (FAQ)”What is prospective short-circuit current?
Section titled “What is prospective short-circuit current?”It is the maximum current that could flow at a point of the installation if a solid short circuit occurred. It is obtained by dividing the supply voltage by the total impedance of the fault loop.
What is the basic formula for calculating short-circuit current?
Section titled “What is the basic formula for calculating short-circuit current?”The fundamental formula is Icc = V / Z, where V is the voltage at the fault point and Z is the loop impedance, which includes source, conductors, and connections.
How is loop impedance measured in the field?
Section titled “How is loop impedance measured in the field?”A fault loop impedance meter is used, which injects a reduced current between phase and ground and measures the voltage drop, calculating Z = Vmeasured / Iinjected.
Why is it indispensable to calculate Icc when designing an installation?
Section titled “Why is it indispensable to calculate Icc when designing an installation?”To select protective devices with sufficient breaking capacity and avoid damage due to electric arc, fire, or explosion in the event of a fault.
What is the difference between symmetric and asymmetric short-circuit current?
Section titled “What is the difference between symmetric and asymmetric short-circuit current?”Symmetric is the RMS value of the pure alternating component, while asymmetric includes a transient DC component that raises the first peak up to 2.5 times the symmetric peak value.
Does operating temperature affect the Icc value?
Section titled “Does operating temperature affect the Icc value?”The resistivity of conductors increases with temperature, which increases Z and slightly reduces Icc. In precision calculations, the resistivity at the expected temperature during the fault is used.
References
Section titled “References”- engineeringtoolbox.com: https://www.engineeringtoolbox.com/electrical-formulas-d_455.html
- allaboutcircuits.com: https://www.allaboutcircuits.com/textbook/direct-current/chpt-16/voltage-current-calculations/
- electrical4u.com: https://www.electrical4u.com/short-circuit-current-of-circuit-breaker/